2.1 Question #12

12. [-/4 Points] DETAILS SCALC8 2.1.030. (a) If G(x) = x2 - 3x + 3, find G'(a) and use it to find equations of the tangent lines to the curve y = x2 - 3x + 3 at the points (0, 3) and (4, 7). G'(a) = Y1 ( X ) = (passing through (0, 3)) Y2 ( X) = (passing through (4, 7)) (b) Illustrate part (a) by graphing the curve and the tangent lines on the same screen. 20 20 G(X ) yz 10- 10 -10 -5 -X 5 10 -10 -5 X 5 10 y1/ /10- -10 -20 G ( X ) 20 O O 4 - 4 20- G (X ) y1 10 10/ V2 -10 -5 L X 5 10 -10 y1 10 -10 !101 20 -20 G (X ) O O