2-18. Two springs connected in series shown in Fig. P2.18 can be represented by a single...

 

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2-18. Two springs connected in series shown in Fig. P2.18 can be represented by a single equivalent spring. The stiffness of the equivalent spring is given by keq k1k2 k1 + k2 (2.63). where k and k are the spring constants of the two springs. If keq = 1.2 N/m and k = 2k - 1 N/m find k and k as follows: a. Substitute the values of keq and k in equation (2.63) and obtain the quadratic equation for k. b. Solve the quadratic equation for k obtained in part (a) by completing the square and the quadratic formula. Also, compute the corresponding values of k2. 0000 k Figure P2.18 Series combination of two springs. k2 2-18. Two springs connected in series shown in Fig. P2.18 can be represented by a single equivalent spring. The stiffness of the equivalent spring is given by keq k1k2 k1 + k2 (2.63). where k and k are the spring constants of the two springs. If keq = 1.2 N/m and k = 2k - 1 N/m find k and k as follows: a. Substitute the values of keq and k in equation (2.63) and obtain the quadratic equation for k. b. Solve the quadratic equation for k obtained in part (a) by completing the square and the quadratic formula. Also, compute the corresponding values of k2. 0000 k Figure P2.18 Series combination of two springs. k2