Question: 22) y = 2(x 2)^2 + 5 Vertex: (2, 5) Axis of symmetry: x = 2 Opens up Minimum value 5 Domain: (, ) Range:

22) y = 2(x 2)^2 + 5 Vertex: (2, 5) Axis of symmetry: x = 2 Opens up Minimum value 5 Domain: (, ) Range: [5, ) 23) f(x) = (x 1)^2 + 2 Vertex: (1, 2) Axis of symmetry: x = 1 Opens down Maximum value 2 Domain: (, ) Range: (, 2] 24) g(x) = (x + 4)^2 Vertex: (4, 0) Axis of symmetry: x = 4 Opens down Maximum value 0 Domain: (, ) Range: (, 0] 25) y = (1/3)(x + 2)^2 1 Vertex: (2, 1) Axis of symmetry: x = 2 Opens up Minimum value 1 Domain: (, ) Range: [1, ) Write the equation of each parabola in vertex form: 26) Vertex (1, 2); Point (2, 5) Use y = a(x 1)^2 + 2. Plug (2, 5): 5 = a(1) + 2 a = 7 Equation: y = 7(x 1)^2 + 2 27) Vertex (3, 6); y-intercept 2 point (0, 2) Use y = a(x 3)^2 + 6. Plug (0, 2): 2 = 9a + 6 a = 4/9 Equation: y = (4/9)(x 3)^2 + 6 28) Vertex (0, 5); Point (1, 2) Use y = a(x 0)^2 + 5. Plug (1, 2): 2 = a + 5 a = 7 Equation: y = 7x^2 + 5 put it in a way 16 year old would write it

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