Question: 220% 4+ MCR3U - Functions Unit 7 - Sequences and Series 35. Write out the first 10 terms of the recur Date [ / 2]

220% 4+ MCR3U - Functions Unit 7 - Sequences and220% 4+ MCR3U - Functions Unit 7 - Sequences and220% 4+ MCR3U - Functions Unit 7 - Sequences and
220% 4+ MCR3U - Functions Unit 7 - Sequences and Series 35. Write out the first 10 terms of the recur Date [ / 2] 1; 62 = tn = th-2- tn-1 n >3 t1 t2 t3 ts to t7 to 26. - 11 , - 23 ,- 353- 717 For the arithmetic sequence 37, 25, 13,..., determine the following What is the formula for the general term (tn)? d = - 12 = 37+ (- 12n+12) th = 49- 12n b. What is the value of the 10th term? [ /1] th = 49 - 12n to = - 71 to = 49-12(10) to = 49 - 120 - .. 10th - term is - 71 c. What is the sum of the first 8 terms? S. = h (z(a)+ (n-1)d) -S, = 8/2 ( 37 ) + (8- 1)-12) [ 191 2 Se= = 80 2 . the sum of Sn= n(2(37) + (1-1)-12) 2 the first 8 ten 2 So = - 40 is - 40 7. For the arithmetic sequence, the following terms are known: t5 = 17, t15 = 42. What is the formula for the general term (tn)? 17= 0+ (5-1)1 (2 42 = a + ( 15-1)d 17 = 0+ 4d 42 - at 14d 2 -0 a + 14 ( 2.5 ) = 42MCR3U - Functions Unit 4 - Trigonometric Equations and Identities Date 18. What is the measurement of the unknown side, present your answer in exact (radical) form 4 cm/30 /60 19. Apply CAST and trig ratios of special angles to evaluate the expressions below [ / 4] a) tan(2109) = tan (270-60) b ) sec (1350 ) tan ( 220' - 0) = cotle ) tan ( 210 ) = cot (60 ) cot ( 60) =- tan ( 210' ) = - ILM 1 1 c) sin(-609) d) cos(270) = - sin (60) 2 = 0 Solve for all values of the unknown angle o where 0

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