Question: 225a+96 +25c 75 ac 45 ab - 15 bc = 0 - - (450a + 1862 + 50c - 90 ab - 30 bc

225a+96 +25c 75 ac 45 ab - 15 bc = 0 -

225a+96 +25c 75 ac 45 ab - 15 bc = 0 - - (450a + 1862 + 50c - 90 ab - 30 bc - 150 ac) = 0 225a +962 +25c + 225a +962 + 25c - 2 x 15a x 36-2 5 15 ac - 2 x 31 5c =0 (15 a 36) + (36 - 5c) + (5c - 15 a) -

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