2^32 bytes of byte addressable

Cache memory is 2^15

This was cut off for some odd reason

Anyways

Answer B C D E and please explain I would like to learn

7. [10 points] Suppose a computer has bytes of byte-addressable main memory and a cache size of bytes, and each cache block contains 32 bytes a) How many blocks of main memory are there? ( b) How many blocks of cache memory are there? ( c) If this cache is direct-mapped, what is the format of a memory address as seen by the cache; that is, the the size of block size of the tag field field and the size of the offset field d) If this cache is fully associative, what is the format of a memory address as seen by the cache; that is, the and the size of the size of the tag field offset field e) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache; , the and the size of the that is, the size of the tag field size of set field offset field