Question: 25 C is the 32. E = E -0.059/n log Q (Nernst equation) [H] = 1.0 M initially, Poz= 1.0 atm Un ghignals 4e +

25 C is the 32. E = E -0.059/n log Q (Nernst equation) [H] = 1.0 M initially, Poz= 1.0 atm Un ghignals 4e + O(g)+4H*(aq) 2HO(1) E=1.23V Based on the information above, which statement is correct? 5102 a. n = 1, since one mole of oxygen is being considered. b. Addition of base should result in an E value, which is less than 1.23 V. C. E is independent of the pH of the solution. d. Q = [HO1 [0] [H*] LOTOOL

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