25 m/s 137.0 h = . 90 m 9. A projectile is shot from the edge of a cliff 90 m above ground level with an initial speed of 25 m/s at an angle of 37.0 with the horizontal, as shown in the figure to the right. (a) Determine the time taken by the projectile to hit point P at ground level. (b) Determine the range X of the projectile as measured from the base of the cliff. (c) At the instant just before the projectile hits point P, find the horizontal and the vertical components of its velocity, (d) the magnitude of the velocity, and the angle made by the velocity vector with the horizontal.(f) Find the maximum height above the cliff top reached by the projectile. (g) Plot the graphs of the horizontal and vertical velocities as a function of time 40 Horizontal 10 Component of Velocity of Time (s) (m/s) (-10)- (-20)- (-30)1- (-40) 40 30 20 Vertical 10 - Component of Velocity 0 Time (s) (m/s) (-10)-- (-20) (-30)1- (-40)