Question: . 28 Jazit Con 4: (c) 1: function Func(n) 2: = 0 3: for i=n to 3n do for j = 2i + n to
. 28 Jazit Con 4: (c) 1: function Func(n) 2: = 0 3: for i=n to 3n do for j = 2i + n to 2i+ na do 5: for k = [log (n)] + j2j3 to na +32;3 do 6: r = x + i - jk c 7: end for 8: end for 9: end for 10: return r 11: end function
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