Question: 2.exercise p=15%=.15 margen de error =3$=.03 n=Z^2 p(1-p)/(m^2)= 1.65^2 * .15(1-.15)/(.03)^2= .3471/.0009=385 b. n=N Z^2 *p(1-p)/m^2(N-1)+Z^2 * p(1-p)= 17.355/.3912=44 A. Use the space provided in
2.exercise
p=15%=.15
margen de error =3$=.03
n=Z^2 p(1-p)/(m^2)= 1.65^2 * .15(1-.15)/(.03)^2= .3471/.0009=385
b. n=N Z^2 *p(1-p)/m^2(N-1)+Z^2 * p(1-p)= 17.355/.3912=44
A. Use the space provided in the following table with the data from problem #2 to determine
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