2LiOH (s) --> Li2O (s) + H2O (l) Delta H= 379.1 kJ

LiH (s) + H2O (l) --> LiOH (s) = H2 (g) Delta H= -111.0 kJ

2H2 (g) + O2 (g) --> 2H2O (l) Delta H= -285.9 kJ

Compute Delta H in kJ for the 2LiH (s) + O2 (g) --> Li2O (s) + H2O (l)

 

 

 

 

 

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Answers Given 2LIOH s Blank Equation Li20 s H20 1 AH 3791 kJ 1 LiH s H20 1 A Blank ... View the full answer