Question: 2y3 - y2 + 2y - 1 2y2 - 3y + 1 f(y) = y3 - y2 ty - 1 and g(y) =412 - 4y

2y3 - y2 + 2y - 1 2y2 - 3y +

2y3 - y2 + 2y - 1 2y2 - 3y + 1 f(y) = y3 - y2 ty - 1 and g(y) =412 - 4y + 1 f(y)xg(y) =

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