$(30)$ When $S{O}_{3(g)}$ is decomposed at the constant pressure $P$

and $T=1000K,$ the partial pressure of $O_2$ in the equilibrium

gas is $0\mathrm{.}05$atm.

a$)$ What is the pressure $P?$

b$)$ If the pressure of this equilibrated gas is increased to $1\mathrm{.}5$

atm, to what value must be the temperature to decreased

to produce a gas mixture in which $p{O}_2=0\mathrm{.}05$atm $?$

$G^o=-94600+89\mathrm{.}37T$ for $S{O}_2(g)+\frac{1}{2}{O}_2(g)=S{O}_3(g)$