Question: 3. [0/2 Points] DETAILS PREVIOUS ANSWERS OBINPHYS8 9.P.008. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER My Notes X Height of object (ho) = 2.1 cm,

3. [0/2 Points] DETAILS PREVIOUS ANSWERS OBINPHYS8 9.P.008. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER My Notes X Height of object (ho) = 2.1 cm, Height of image (hi) = (2.6)*(2.1) cm Image distance (di) = 19 cm = (-1)(*2.1*19)(2.6*2.1) =-18/2.6 =-6.923077 CLEAR SAVE A 2.1 cm-tall object stands in front of a converging lens. It is desired that a virtual image 2.6 times larger than the object be formed by the lens. How far from the lens (in cm) must the object be placed to accomplish this task, if the final image is located 19 cm from the lens? -6.923077 X cm Need Help? Read It Submit

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