$3\mathrm{.}10.$ Calculate the reversible work done in compressing $1($ft$)3$ of mercury at a constant temperature of $32($F$)$ from $1($atm$)$ to $3000($atm$).$ The isothermal compressibility of mercury at $32($F$)$ is: $/($atm$)1=3\mathrm{.}91060\mathrm{.}1109$ P$/($atm$)$