$3.(16$ points$)$ We want a Bash script which will take a list of usernames on the command line and print out which of those users is currently logged on$,$ in alphabetical order, on one line. For each of the following scripts, indicate whether it works. If it does not, show how to fix it by changing the fewest characters possible.

Script A

Works as is$.$ Needs fixing.

$```$

for name in $*$

do

who $|$ grep $-$w $"-$$name" $|$ sed $-$e $\text{'}$s$/.//\text{'}|$ uniq

done $|$ sort $|$ tr $\text{'}$

$\text{'}\text{'}\text{'}$

echo

$```$

Script B

Works as is$.$ Needs fixing.

$```$

search$=\text{'}(\text{'}$$$($ echo $$*|$ sed $\text{'}$s$//$l$/$g$\text{'})\text{'})\text{'}$

who $|$ grep $-$E $"^$$search" $|$ awk $\text{'}\{$print $$1\}\text{'}|$ sort $-$u $|$ tr $\text{'}$

$\text{'}\text{'}\text{'}$

echo

$```$

Script C

Works as is$.$ Needs fixing.

$```$

for name in $@

do

users $|$ grep $-$q $"^$$name"

if $(($ $$?==0))$ ; then

echo $name

fi

done $|$ sort $|$ uniq $|$ tr $\text{'}$

$\text{'}\text{'}\text{'}$

echo

$```$

Script D

Works as is$.$ Needs fixing.

$```$

for name in $#

do

who $|$ sed $-$n $"/$~$name $/$s$/.*/$p$"$

done $|$ sort $-$u $|$ tr $\text{'}$

$\text{'}\text{'}\text{'}$

echo

$```$