Question: 3. (10 points) For relation R(A,B,C,D) and FD= {AB->C, BC->D, CD->A,AD->B}, is there any FD violate(s) the BCNF rules? Justify your answer. Hint: For each

 3. (10 points) For relation R(A,B,C,D) and FD= {AB->C, BC->D, CD->A,AD->B},

3. (10 points) For relation R(A,B,C,D) and FD= {AB->C, BC->D, CD->A,AD->B}, is there any FD violate(s) the BCNF rules? Justify your answer. Hint: For each X->Y, it has to be trivial or X is the superkey. Otherwise it violates BCNF rule. 4. (10 points) R(A,B,C,D,E) and FD={BC->E}. Let R(A,B,C,D,E) be decomposed into two relations R1(A,B,C,D), R2(B,C,E). Determine whether the decomposition is lossless. Hint: Assume Rwas decomposed into two relations, say R1 and R2, if the common attributes between R1 and R2 determines R1 or R2, then this decomposition is lossless

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