Question: 3. (10 points) Suppose a complex number z satisfies the equation 227 - (3 +8i)z - (m + 4i) = 0. Given that m is

3. (10 points) Suppose a complex number z satisfies the equation 227 - (3 +8i)z - (m + 4i) = 0. Given that m is a real constant and that one of the two solutions is real, find the two solutions of the above complex quadratic equation. (Hint: The real solution is easy to find. To find the other solution, use the fact that the two solutions zi, z2 of the quadratic equation az- + bz + c = 0 satisfy zi + 22 = -b/a.)

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