Question: 3 . ( 2 5 points ) The equations are given as: y 0 0 1 = y 1 + 2 y 0 2 y

3.(25 points) The equations are given as:
y 001= y1+2y 02 y1+ D1 y1 D2 y 002= y22y 01 y2 D1 y2 D2 D1=((y1+)2+ y 22)3/2 D2=((y1 )+y 22)3/2 Use parameter: =0.012277471, =1, y1(0)=0.994, y 01(0)=0, y2(0)=0, y02(0)=2.0015851063790825. It is known that the solutions would become periodic, i.e., the object will following a certain orbit. When t =17.065211656 it would complete one full round of its orbit. 1. Write a program that would solve the system with the classical 4th order Runge-Kutta method, but reduce the step number to 6000.

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