$3-34.$ A shear spring is made by bonding thb rubber

annulus to a rigid fixed ring and a plug. When an axial load

$P$ is placed on the plug, show that the slope at point $y$ in the

rubber is $d\frac{y}{d}r=-tan=-tan(\frac{P}{2hGr}).$ For small

angles we can write $d\frac{y}{d}r=-\frac{P}{2hGr}.$ Integrate this

expression and evaluate the constant of integration using

the condition that $y=0$atr$=r_o.$ From the result calculate

the deflection $v=$ of the plug