3 3 h) 0.406 Find the probability that X is at most 26.92. 1. A family...

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3 3 h) 0.406 Find the probability that X is at most 26.92. 1. A family is selected at random form the province of Saskatchewan. Let X denote the income of the family (in thousand dollars). It can be shown that X has a normal distribution with mean 30.2 and standard deviation 5.3. Find the probability that X is between 28.92 and 35.48. a) 0.543 b) 0.261 f) 0.534 g) 0.569 c) 0.383 d) 0.396 i) 0.331 e) 0.636 j) 0.436 2-3 core DD a) 0.335 b) 0.298 c) 0.099 d) 0.268 e) 0.421 1) 0.564 g) 0.699 h) 0.148 i) 0.007 j) 0.754 Find the probability that X is at least 26.45. L a) 0.444 b) 0.575 c) 0.761 d) 0.669 e) 0.218 f) 0.742 g) 0.174 h) 0.819 i) 0.411 Find the probability that X is less than 25.57 or more than 36.22. j) 0.667 C6 a) 0.151 b) 0.528 c) 0.319 d) 0.254 e) 0.976 f) 0.881 g) 0.391 h) 0.568 i) 0.836 j) 0.478 hew The Ph percentile of a distribution is defined to be the number Xp such that the proportion of individuals having X below the value of Xp is P/100. Find the 80th percentile of the distribution of X. 96 bi 11.8 130 mee my 2-care-ies to yo 3 3 h) 0.406 Find the probability that X is at most 26.92. 1. A family is selected at random form the province of Saskatchewan. Let X denote the income of the family (in thousand dollars). It can be shown that X has a normal distribution with mean 30.2 and standard deviation 5.3. Find the probability that X is between 28.92 and 35.48. a) 0.543 b) 0.261 f) 0.534 g) 0.569 c) 0.383 d) 0.396 i) 0.331 e) 0.636 j) 0.436 2-3 core DD a) 0.335 b) 0.298 c) 0.099 d) 0.268 e) 0.421 1) 0.564 g) 0.699 h) 0.148 i) 0.007 j) 0.754 Find the probability that X is at least 26.45. L a) 0.444 b) 0.575 c) 0.761 d) 0.669 e) 0.218 f) 0.742 g) 0.174 h) 0.819 i) 0.411 Find the probability that X is less than 25.57 or more than 36.22. j) 0.667 C6 a) 0.151 b) 0.528 c) 0.319 d) 0.254 e) 0.976 f) 0.881 g) 0.391 h) 0.568 i) 0.836 j) 0.478 hew The Ph percentile of a distribution is defined to be the number Xp such that the proportion of individuals having X below the value of Xp is P/100. Find the 80th percentile of the distribution of X. 96 bi 11.8 130 mee my 2-care-ies to yo