Question: 3 / 4 100% 4. (2+2 points) Using the same reduction as in the previous question, state a recurrence T'(n) that expresses the worst case

 3 / 4 100% 4. (2+2 points) Using the same reduction

3 / 4 100% 4. (2+2 points) Using the same reduction as in the previous question, state a recurrence T'(n) that expresses the worst case running time of the recursive algorithm. From this recurrence, find a tight (Big-Theta) expression for T'). Hint: the Master Theorem may be the easiest solution here. Now consider the problem of finding the concatenation of all strings whose length is a perfect square from a list, where the Boolean function issqr(n) determines whether or not n is a perfect square (that is, issqr(n) is true iff n is an integer of form n=r? for some integer ): Concatenation of All Strings whose Length is a Perfect Square (CONCATSQR) Input: Sla...bl, a list of strings. Output: c = Stil 1 ... | Slim where I <.... issqr for all is k sm and false other indices j otherwise c="&" if s contains no string whose length a perfect square. points let represent the solution of concatsqr problem on input sta...b state two different divide-and-conquer self-reductions above. give recursive algorithms pseudo-code based your to solve problem. what are worst-case runtimes solutions you have obtained runtimes. do not need show work. w using same reduction as in previous question recurrence t that expresses worst case running time algorithm. from this find tight expression hint: master theorem may be easiest here. now consider finding concatenation strings square list where boolean function determines whether or n true iff an integer form some input: sla...bl strings. output: ... slim i>

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