Question: 3 . 5 There arc several ways to evaluate PN ( x ) = c 1 + c 2 x + + cNxN - 1

3.5 There arc several ways to evaluate PN(x)= c1+ c2x + + cNxN-1. As a first algorithm we could use P:= c1 for i =2,3,..., N begin P:=P+ci * x i - l end i. How many multiplications does this algorithm require? A better approach is based on the nested form of PN(x) used in Section 3.3:

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