$"3/7"$ and not $"\frac{03}{07}".$ The function is to set days$\_$member of the invoking Date object to the number of days for the given date from January $\frac{?}{\text{b}\text{a}\text{r}}(1)$ and to return a reference to the invoking object. Hint: Use the class$-$level constant array to help determine the value for days$\_.$

For example, given the following code segment:

$d=-\frac{2}{{14}^{In}}$;

cout $d$ endl;

Here's its expected output:

The date $\frac{02}{14}$ is $44$ day$($s$)$ from January $1$

The overloaded $$ operator as a member function to support the comparison between a Date object on the left and a string on the right in the format $"$M$/$D$".$ Again, the date may have one or two digits in the month and year. The function shall retum true if the Date object on the left of $>=$ has a later date than the string object on the right. Otherwise, false shall be returned. For example, given the following code segment:

today $="9/26"$;

cout $$ boolalpha;

cout $$ "today $\frac{9}{10}$ returns $"$ today $($:$\frac{9}{\frac{?}{?}}{10}^{**}\}$ endl;

Here's its expected output:

today $\frac{9}{10}$ returns true

today $\frac{9}{30}$ returns false

The overloaded $$ operator as a member function to support the comparison between a Date object on the left and a string on the right in the format $"$M$/$D$".$ Again, the date may have one or two digits in the month and year. The function shall retum true if the Date object on the left of $$ has an earlier date than the string object on the right. Otherwise, false shall be retumed. For example, given the following code segment:

Date today;

$)=(\frac{9}{\frac{?}{?}}{10}^{**})=(\frac{9}{\frac{?}{?}}{30}^{\text{@}}$

Here's its expected output:

today $\frac{9}{10}$ returns false

today $=\frac{9}{30}$ returns true