$39.$

$40.$

$41.$

$42.$

In Problems $39-42,$ use the substitution y $=($x $-$ xo$)$m to

solve the given equation.

$($x$+3)2$y$"-8($x$+3)$y$\text{'}+14$y $=0$

$($x$-1)2$y$"-($x$-1)$y$\text{'}+5$y$=0$

$($x$+2)2$y$"+($x$+2)$y$\text{'}+$y$=0$

$($x$-4)2$y$"-5($x$-4)$y$\text{'}+9$y$=0$