$3.$ Implement row$\_$sums

Read the specification of the function row$\_$sums in the module funcs. Implement this function according to its specification. Note that this function returns a list of numbers. You are going to want to use the double$-$accumulator pattern for this problem. The outside for$-$loop accumulates the list to return. Inside of the for$-$loop you have an accumulator $($and another for$-$loop$)$ to accumulate the sum for each row.

When you have implemented the function, test your answer with the test script before moving on to the next function.

def row$\_$sums$($table$)$:

$"""$

Returns a list that is the sum of each row in a table.

This function assumes that table has no header, so each row has only numbers in it$.$

Examples:

row$\_$sums$([[0\mathrm{.}1,0\mathrm{.}3,0\mathrm{.}5],[0\mathrm{.}6,0\mathrm{.}2,0\mathrm{.}7],[0\mathrm{.}5,1\mathrm{.}1,0\mathrm{.}1]])$ returns $[0\mathrm{.}8,1\mathrm{.}5,1\mathrm{.}7]$

row$\_$sums$([[0\mathrm{.}2,0\mathrm{.}1],[-0\mathrm{.}2,0\mathrm{.}1],[0\mathrm{.}2,-0\mathrm{.}1],[-0\mathrm{.}2,-0\mathrm{.}1]])$ returns $[0\mathrm{.}3,-0\mathrm{.}1,0\mathrm{.}1,-0\mathrm{.}3]$

Parameter table: the nested list to process

Precondition: table is a table of numbers. In other words,

$(1)$ table is a nested $2$D list in row$-$major order,

$(2)$ each row contains only numbers, and

$(3)$ each row is the same length.

$"""$