Question: 3 * n ^ 2 + 2 * n * log ( n ) = big - omega ( n ^ 2 ) why is

3*n^2+2*n*log(n)= big-omega(n^2) why is it true?

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Programming Questions!