$3-$phosphoglycerate $2-$phosphoglycerate

$G=+4\mathrm{.}40k\frac{J}{m}ol$

$($a$)$ Calculate the equilibrium constant, $K_{eq},$ for this reaction at $25C.$

$($b$)$ If the actual $G$ of the intracellular reaction is $+25k\frac{J}{m}ol,$ will a net forward or a net revers reaction be required to reach equilibrium? Explain.

$($c$)$ Under what intracellular conditions does $G=G^{\text{'}}?$