Question: ( 3 points ) For a column, the ASD design strength is expressed by: a . b M n b . M n c (

(3 points) For a column, the ASD design strength is expressed by:
a.bMn
b.Mnc
(c.)Pnc
d.cPn
(3 points) A W12\times 190 is used as a column. If the effective length of the column is 32 feet, according to the ASD design method, the maximum axial load the column would be allowed to take is:
(Hint: The answer is in the Manual. Remember units)
(3 points) For flexural members, the ASD Resistance Factor, b, applied to the member's nominal moment capacity, Mn, to determine the available flexural strength is:
a.1.5
b.2.0
c.1.67
d. any of these, depending on the day of the week
(3 points) In beams, using the LRFD method, the allowable shear strength of the section is expressed by:
a.vPn
b.vvvn
(c.)Vnv
d.Pnv
(3 points) In the LRFD method, to determine the allowable strength of a member, the factor is applied to:
a. the ultimate strength
b. the allowable strength
c. the nominal strength
d.0.5 value of K can never be less than:
b.1.0
(c.)2.0
a.10
(Hint: The answer is in the Manual)
(3 points) Using the ASD method, the (Hint: sidesway will not occur.
used as a beam is:
a. true
b. false
(3 points) Using the LRFD method, what is
(Hint: The answer is in the Manual)
( 3 points ) For a column, the ASD design

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