Reaction of [(CH2=CH2)2RHCI]2 (A) with two equivalents of a phosphine ligand under nitrogen results in displacement...

 

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Reaction of [(CH2=CH2)2RHCI]2 (A) with two equivalents of a phosphine ligand under nitrogen results in displacement of ethylene by phosphine. With triethylphosphine, the reaction yields a dimer, [RhCl(PET3)2]2.(B). With 'Pr'P, a monomeric N2 complex is formed, RhCl(N2)(P'Pr3)2].(C). Draw structures of A, B and C. Explain why different results are seen with the two different phosphines. Reaction of [(CH2=CH2)2RHCI]2 (A) with two equivalents of a phosphine ligand under nitrogen results in displacement of ethylene by phosphine. With triethylphosphine, the reaction yields a dimer, [RhCl(PET3)2]2.(B). With 'Pr'P, a monomeric N2 complex is formed, RhCl(N2)(P'Pr3)2].(C). Draw structures of A, B and C. Explain why different results are seen with the two different phosphines.

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The difference between the triethyl phosphine and triisopropylphosphine is the steric hindrance The ... View the full answer