Question: 3. Solve the recurrence relation A(n) = 6A(n - 1) - 11A(n -2) + 6A(n - 3) subject to initial values A (1) = 2,

3. Solve the recurrence relation A(n) = 6A(n - 1) - 11A(n -2) + 6A(n - 3) subject to initial values A (1) = 2, A(2) = 6, A(3) = 20. Hint: See example 2.4.6 on page 141 of the course text

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