3. Threshold voltage Vth = 0.7 V, nox = 200 A/V, pox = 200 A/V, W/L...

Transcribed Image Text:

3. Threshold voltage Vth = 0.7 V, μnСox = 200 μA/V², μpСox = 200 μA/V², W/L = 5. Ignore channel length modulation λ = 0 and body effect. VDD = 1.8V. (a) In Fig. 3(a), draw the voltage transfer curve of Vout when Vin is DC from 0V to 1.8V. Specify the operating point Vout and Vin at cut-off, linear, saturation region (b) In Fig. 3(b), draw the VTC. (c) In Fig. 3(c), draw the VTC. VDD VDD 20k92 -OV Vino out Vin -V 20ΚΩ (a) (b) Fig. 3 VDD J out Vin NMOS -OV out PMOS (c) 4. When body effect must be taken into account, and using VSB=1V to simply your calculation. Redraw the problem 3 (a), (b), (c). V th=V tho+7 [√2¢, +V st +VSB - √20, 20, = 0.7V, y = 0.4√1/2 3. Threshold voltage Vth = 0.7 V, μnСox = 200 μA/V², μpСox = 200 μA/V², W/L = 5. Ignore channel length modulation λ = 0 and body effect. VDD = 1.8V. (a) In Fig. 3(a), draw the voltage transfer curve of Vout when Vin is DC from 0V to 1.8V. Specify the operating point Vout and Vin at cut-off, linear, saturation region (b) In Fig. 3(b), draw the VTC. (c) In Fig. 3(c), draw the VTC. VDD VDD 20k92 -OV Vino out Vin -V 20ΚΩ (a) (b) Fig. 3 VDD J out Vin NMOS -OV out PMOS (c) 4. When body effect must be taken into account, and using VSB=1V to simply your calculation. Redraw the problem 3 (a), (b), (c). V th=V tho+7 [√2¢, +V st +VSB - √20, 20, = 0.7V, y = 0.4√1/2

Answer rating: 100% (QA)

Answer The voltage transfer curve of Vout when VIn is DC from 0V to 18V is shown below CMOS inverter voltage transfer curve The operating point Vout and VIn at cutoff linear and saturation regions are ... View the full answer