(3) Use integration by parts to create a recursion formula for Jn. Simplify your answer as much as possible. Your answer should look something like Jn = something Jn2

In this assignment we will prove a classic formula for /2 : limn(133557(2n1)(2n1)(2n+1)224466(2n2)(2n)(2n))=2 Another way to write this is limn(i=1n(2i1)(2i+1)(2i)(2i))=2 Write out answers to questions (1)-(10). Recall that integration by parts for definite integrals states that abf(x)g(x)dx=f(x)G(x)x=ax=babf(x)G(x)dx Define Jn=0/2cosnxdx