Question: (30 points) Translate the high-level code below into MIPS assembly. You can assume that $s0 holds the value of x and $sl holds the value

 (30 points) Translate the high-level code below into MIPS assembly. You

(30 points) Translate the high-level code below into MIPS assembly. You can assume that $s0 holds the value of x and $sl holds the value of y. int x, yi X X = 0; = x >> 4; = x + 2; (35 points) Translate the high-level code below into MIPS assembly. Assume that $t1 holds the value of var and $t2 holds the value of i. Assume that you must store the value of i to address 0x2000A000 at the end of this code. char i; int var = 0; i--; if(var 0) var 10; else var = 20; (35 points) Say you wish to write a program that takes two arrays, X and Y, sums the corresponding element of each, and writes the result into a third array Z. Each array has 15 elements and is of the data type SHORT (16 bits). You know that the base addresses of X, Y, and Z are 0x00100000, 0x00200000, and 0x00300000. Specify which address(es) are used up by each index of each array. Example (although incorrect for this question): X[0] uses 0x00100000, 0x00100001, 0x00100002, 0x00100003, 0x00100004, Ox00100005 X[1] uses Ox00100006, 0x00100007, 0x00100008, 0x00100009, 0x0010000A, Ox0010000B Etc

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