Question: Assume an object has the initial horizontal velocity vector: V=3.25 +4.359 The object suffers the following acceleration for = 2.5 s: a=2.458-3.009 a. (10

Assume an object has the initial horizontal velocity vector: V=3.25 +4.359 The object suffers the following

Assume an object has the initial horizontal velocity vector: V=3.25 +4.359 The object suffers the following acceleration for = 2.5 s: a=2.458-3.009 a. (10 Points) Calculate the final velocity vector, ignoring gravity. b. (10 Points) Assuming 8= 19.80 m/s 2 and the object takes precisely 1.330590555 s to hit the ground, how high was the object initially, in meters? Answer to 7 sig-figs, which is 6 decimal places.

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