Question: 360 Consider the following L.P. Model: Maximize Subject to 320 Z = 15X1 +5X2 3X1 + 1X2 300 1X1 + 1X2 s 200 1X, $100

360 Consider the following L.P. Model: Maximize

360 Consider the following L.P. Model: Maximize Subject to 320 Z = 15X1 +5X2 3X1 + 1X2 300 1X1 + 1X2 s 200 1X, $100 1X2 250 X1, X220 (C2) 280 240 (C4) 200 160 120 80- Constraints. C1. C2 C3 and C4 have been drawn on the graph to the right. a) Using the point drawing tool, locate all the corner points for the feasible area on the graph. The optimum solution (using a corner point) is: X1 -round your response to four decimal places). X2=(round your response to two decimal places). Optimal solution value z =(round your response to two decimal places). 40- 0- 0 40 80 120 160 200 240 280 320 360 X1 b) Is there more than one optimal solution

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