37 Solve for N as a function of t, we get N = a(1-1) Some calculation...

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37 Solve for N as a function of t, we get N = a(1-1) Some calculation details: +(1-a)) 38 Now let z = 1, a = 0.33, b = 2.15 and t = 0.5, the N you calculated in 37 is 37 Solve for N as a function of t, we get N = a(1-1) Some calculation details: +(1-a)) 38 Now let z = 1, a = 0.33, b = 2.15 and t = 0.5, the N you calculated in 37 is

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Given the equation N za1 eatight b we can substitute the values z 1 a 033 b 215 and ... View the full answer