Question: (3/7)^3x + 1 = (7/3)^5x - 9 Solve for x Remove parentheses. (3/7)^3x + 1 = (7/3)^5x - 9 Raising the fraction 3/7 to the

(3/7)^3x + 1 = (7/3)^5x - 9 Solve for x Remove parentheses. (3/7)^3x + 1 = (7/3)^5x - 9 Raising the fraction 3/7 to the power 3x + 1 is the same as raising the numerator and denominator each to the power 3x + 1.

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