Question: 3x (1 point) Solve the initial value problem y' y(5) = 0, and find the interval in which the solution is defined. 1 + 5y

3x (1 point) Solve the initial value problem y' y(5) = 0, and find the interval in which the solution is defined. 1 + 5y Solution is y = (3x^2/5 -374/25)^(1/2) -1/5 Solution is defined on (-infinity,-(374/15)^(1/2)]U[(374/15)^(1/2), infinity) (Enter your answer using interval notation.)

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