Question: 4 . 1 7 Program # 4 : Hailstone sequence C + + This lab will be available until June 2 9 th , 1

4.17 Program #4: Hailstone sequence C++
This lab will be available until June 29th,11:59 PM PDT
Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence:
If n is even, divide it by two
If n is odd, multiply it by 3 and add 1(i.e.3n+1)
Continue until n is 1
Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so
that five integers, each separated by a tab character (??t), are printed per line. End the output with a newline. DO NOT output a tab after the
last value on a line.
The output format can be achieved as follows:
cout n"??t";
Ex: If the input is:
25
the output is:
Handling input error
If the user does not enter a positive integer, output an error message and ask them to re-enter a positive integer. Keep doing this until they
enter a positive integer. (Note,0 is not a positive integer.)
Ex: If the input is:
the output is:
4 . 1 7 Program # 4 : Hailstone sequence C + +

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