$4\mathrm{.}1.$ Using the solution of a triangle and the given distances and oriented directions to calculate the final coordinates of $R$ from two triangles ABR and CDR respectively.

$\backslash$table$[[$POINT$,$Y$,$X$,$Direction$/$Distance$],[$A$,-410,000,+191,000,354\mathrm{.}29\mathrm{.}00],[$B$,-427,000,+367,000,176,820]]$

$\backslash$table$[[$POINT$,$Y$,$X$,$Direction$/$Distance$],[$C$,-769,400,+152,780,5\mathrm{.}20\mathrm{.}40],[$D$,-750,000,+354,900,202,990]]$

Oriented directions from R

$\backslash$table$[[$R$-$A$,111\mathrm{.}37\mathrm{.}50],[$R$-$B$,55\mathrm{.}43\mathrm{.}30],[$R$-$C$,239\mathrm{.}57\mathrm{.}30],[$R$-$D$,299\mathrm{.}40\mathrm{.}40]]$

Note: angles r$1$ and r$2$ are not equal

$\backslash$table$[[$Angle of Triangle ABR,Angle of Triangle CDR$]]$