Question: 4. [4 points] We aim to design an MLP network to classify points within the decision boundary shown below, assuming a simple perceptron where the
4. [4 points] We aim to design an MLP network to classify points within the decision boundary shown below, assuming a simple perceptron where the output Y={Y=1,Y=0,ifiwix1Totherwise: The MLP must classify points inside the given shape versus points that are outside. Note that the coordinates of the points on the given shape are: p1=(1,2),p2=(2,1),p3=(1,1) and p4=(2,2). The designed MLP architecture is shown below. The MLP shows the assigned values for some weights and some thresholds. It is also assumed that values of all the biases in the MLP are set to zero. However, weights w2,w3,w4,w8 and thresholds T1,T4 and T5 are missing. Decision boundary (shaded region) To correctly classify the decision boundary above, values of the missing weights w2,w3,w4. w8 and thresholds T1,T4 and T5 (shown in the MLP) must be: (a) w2=1,w3=1,w4=1,w8=1,T1=2,T4=1 and T5=4 (b) w2=1,w3=0,w4=1,w8=1,T1=3,T4=2 and T5=1 (c) w2=1,w3=0,w4=1,w8=1,T1=3,T4=2 and T5=2 (d) w2=1,w3=0,w4=1,w8=1,T1=3,T4=2 and T5=4 (e) w3=1,w3=1,w4=0,w4=0,T1=3,T4=2 and T5=4 4. [4 points] We aim to design an MLP network to classify points within the decision boundary shown below, assuming a simple perceptron where the output Y={Y=1,Y=0,ifiwix1Totherwise: The MLP must classify points inside the given shape versus points that are outside. Note that the coordinates of the points on the given shape are: p1=(1,2),p2=(2,1),p3=(1,1) and p4=(2,2). The designed MLP architecture is shown below. The MLP shows the assigned values for some weights and some thresholds. It is also assumed that values of all the biases in the MLP are set to zero. However, weights w2,w3,w4,w8 and thresholds T1,T4 and T5 are missing. Decision boundary (shaded region) To correctly classify the decision boundary above, values of the missing weights w2,w3,w4. w8 and thresholds T1,T4 and T5 (shown in the MLP) must be: (a) w2=1,w3=1,w4=1,w8=1,T1=2,T4=1 and T5=4 (b) w2=1,w3=0,w4=1,w8=1,T1=3,T4=2 and T5=1 (c) w2=1,w3=0,w4=1,w8=1,T1=3,T4=2 and T5=2 (d) w2=1,w3=0,w4=1,w8=1,T1=3,T4=2 and T5=4 (e) w3=1,w3=1,w4=0,w4=0,T1=3,T4=2 and T5=4
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