Question: 4. . ( . , . ) (a) Z. = 50 -j250 Zo = 100 . 1 = 0.42 , 2 . (3)) l= 0.42


4. . ( . , . ) (a) Z. = 50 -j250 Zo = 100 . 1 = 0.42 , 2 . (3)) l= 0.42 Zo = 1002 z = 50 -j250 Z [ 4-31 (b) Standing wave ratio S-3.6, Z = -0.1662 . Normalized load impedance 2. & 7821. (38) (c) Z, = 60 - 140 Zo = 50 0. Z short stub( ) . stub a stub 1 . (4) 2o = 500 | z = 60 - j400 F (4-C] stub) 4. Use the Smith chart to get the following: (Each problem is a question of punishment, the Smith chart will also be submitted with an answer sheet, the process of solving it will be presented in the Smith chart, and if multiple answers are presented, all can be obtained, and only one is counted as the correct answer). (a) Z. =50-1252 and 2,= 100 is 2 is 1 = 0.47, get impedance z. (3 points) 1 = 0.41 Zo=1005 ZL=50-j25.2 Z [Figure 4-a) (1) Standing wave ratio S-3.6, the first voltage minimum in the load is Znmin=-0.166. Get normalized load impedance Z. (3 points) A single short stub (short-circuit stub) was used to match the Z to 2, stub. Seek the position d of the stub and the length of the stub. (4 points)(C) ZL=60-14020 GO Z =5020D Zo =50.2 ZL = 60-J40.2 (Figure 4-c] Single stub 4. . ( . , . ) (a) Z. = 50 -j250 Zo = 100 . 1 = 0.42 , 2 . (3)) l= 0.42 Zo = 1002 z = 50 -j250 Z [ 4-31 (b) Standing wave ratio S-3.6, Z = -0.1662 . Normalized load impedance 2. & 7821. (38) (c) Z, = 60 - 140 Zo = 50 0. Z short stub( ) . stub a stub 1 . (4) 2o = 500 | z = 60 - j400 F (4-C] stub) 4. Use the Smith chart to get the following: (Each problem is a question of punishment, the Smith chart will also be submitted with an answer sheet, the process of solving it will be presented in the Smith chart, and if multiple answers are presented, all can be obtained, and only one is counted as the correct answer). (a) Z. =50-1252 and 2,= 100 is 2 is 1 = 0.47, get impedance z. (3 points) 1 = 0.41 Zo=1005 ZL=50-j25.2 Z [Figure 4-a) (1) Standing wave ratio S-3.6, the first voltage minimum in the load is Znmin=-0.166. Get normalized load impedance Z. (3 points) A single short stub (short-circuit stub) was used to match the Z to 2, stub. Seek the position d of the stub and the length of the stub. (4 points)(C) ZL=60-14020 GO Z =5020D Zo =50.2 ZL = 60-J40.2 (Figure 4-c] Single stub
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
