Question: 4 da = x2 + 4x + 8 A) 4In x2 + 4x + 8 + C B tan -1 x+2 + C 2 C

4 da = x2 + 4x + 8 A) 4In x2+ 4x + 8 + C B tan -1 x+2 + C

4 da = x2 + 4x + 8 A) 4In x2 + 4x + 8 + C B tan -1 x+2 + C 2 C 4 tan (x + 2) + C D 2 tan -1 + C 2

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