$4-$ IF you know that

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$4-IF$ you know that

$q,$exp$(x)=1+x+\frac{x^2}{2}+\frac{x^3}{3!}+$cdots$={\displaystyle \underset{n=0}{\overset{N}{}}}\frac{x^n}{n!}$

and exp$(1\mathrm{.}25)=3\mathrm{.}4903$

R$.$a$-$ Find the value of the stopping criteria $({}_3)$ that

ensures the results are correct up to single signifieant digit