Question: 4. In simple stereo Z-f B/d. If the baseline B is 0.5 meter, Z is 2.0 meters, and f is 50 millimeters what is the

 4. In simple stereo Z-f B/d. If the baseline B is0.5 meter, Z is 2.0 meters, and f is 50 millimeters what

4. In simple stereo Z-f B/d. If the baseline B is 0.5 meter, Z is 2.0 meters, and f is 50 millimeters what is the value of d in mm? Repeat this process for Z-1 meter, and 0.5 meter to get two more values for d in mm (same f and B). If we are measuring depth at a given value of Z then we have a certain accuracy in e measurement which depends on how much error there is in th computing the disparity. In turn, the error in disparity computation depends on how accurately we can locate a feature such as a line or corner in the image. In practice, the error in computing the location of a feature is fixed; it does not change regardless of the value of Z for that feature. Assume that this error in disparity d for locating a feature is +- 1mm. In other words, for a computed value of disparity d, the true value is d plus or minus Imm. Now for each of the three given values of d computed above, compute two new values for z; z high when d 4. In simple stereo Z-f B/d. If the baseline B is 0.5 meter, Z is 2.0 meters, and f is 50 millimeters what is the value of d in mm? Repeat this process for Z-1 meter, and 0.5 meter to get two more values for d in mm (same f and B). If we are measuring depth at a given value of Z then we have a certain accuracy in e measurement which depends on how much error there is in th computing the disparity. In turn, the error in disparity computation depends on how accurately we can locate a feature such as a line or corner in the image. In practice, the error in computing the location of a feature is fixed; it does not change regardless of the value of Z for that feature. Assume that this error in disparity d for locating a feature is +- 1mm. In other words, for a computed value of disparity d, the true value is d plus or minus Imm. Now for each of the three given values of d computed above, compute two new values for z; z high when d

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