$(4pts)5{\displaystyle \underset{2}{\overset{3}{}}}\frac{5}{\sqrt[\phantom{2}]{3-x}}dx$

${\displaystyle \underset{2}{\overset{3}{}}}\frac{5}{\sqrt[\phantom{2}]{3-x}}dx$

$={\displaystyle \underset{2}{\overset{3}{}}}5(3-x{)}^{-\frac{1}{2}}dx$

$=-10(3-x{)}^{\frac{1}{2}}{|}_x=2^x=3$

$=-10(0{)}^{\frac{1}{2}}-(-10(1{)}^{\frac{1}{2}})$

$=0+10$

$=10$