$4$ points

b$)$ Determine the Bodenstein$-$number Bo in the river by linear regression! The Axial Dispersion Model has the

following analytical solution:

$C^{*}=C*f=\frac{1}{2}*\sqrt[\phantom{2}]{\frac{Bo}{*}}*exp(\frac{-(1-{)}^2}{4*}*Bo)$

In this equation $C^{*}$ is the relative concentration, which can be calculated by signal C from

conductivity measurement times unknown factor f $).$ The linearization leads to the form

$ln(2*\sqrt[\phantom{2}]{*}*C)=\frac{-(1-{)}^2}{4*}*Bo+ln(\frac{\sqrt[\phantom{2}]{Bo}}{f})$

Draw a diagram $ln(2*\sqrt[\phantom{2}]{*}*C)$ versus $\frac{-(1-{)}^2}{4*}$ to determine the Bodenstein$-$number Bo in the river

from the slope!

c$)$ Improve the regression by variation of the mean residence time $($optimisation of linearity$)!$ Complete the

task by calculating the maximum expected TE for locations twice and three times the distance from the

hazardous incident! Attention! What happens regarding Bodenstein$-$number? Discuss the forecast!cobalt and hy$-$ac for hydrochloric acid!$)$

b$)$ Draw a diagram to prove, if the chemical reaction is the controlling factor! Take care to let the linear

function start in the origin of the coordinates $($Diagram on paper required for all points$)!$ Units?

$6$ points

c$)$ Draw a diagram to prove, if the internal diffusion is the controlling factor $($Diagram on paper

required for all points$)!$ Units?

$5$ points

d$)$ Can you improve the model? Assume a certain amount of the cobalt is not in an active state and does

not take part in the reaction! Show the improvement in the diagrams!

$6$ points

e$)$ Estimate the time for $100\%$ conversion for your favourite model! The size of the particles is not

reported in the article. They seem to be very small. Can you give a recommendation regarding other

models, which may fit better?