$(4.)$ The horizontal distance from the back hooves to a horse's center of gravity is $1\mathrm{.}3$ m $.$

The distance from its center of gravity to its front hooves is a smaller distance $0\mathrm{.}6$ m $.$ If

the normal force acting on the horses's front hooves is n$\_($F$)=3900$N$,$ what is the horse's

weight? Note: The n$\_($F$)$ given is the force on both of the front hooves together, so you

do not need to double it$.$

$($a$)$ w$=1232$N

$($b$)$ w$=2668$N

$($c$)$ w$=5070$N

$($d$)$ w$=5700$N

$($e$)$ w$=12350$N

Hint: One of the incorrect answers is $($b$.)$