4. The percentile rank of a Z-score of approximately 0.7295 is around 76.24% or 0.7624 in decimal form. To find the probability that a score with this value, or higher, would be found in the population by chance, we subtract the percentile rank from 1 or 100: 1 - 0.7624 = 0.2376 The probability that a score with a Z-score of approximately 0.7295 or higher would be found in the population by chance is approximately 0.2376 or 23.76%. So, the probability that someone will have a frequency of childhood abuse experiences score than the subject with a Z-score of 0.7295 is approximately 23.76%. What is the general range of z values most likely to be found in a random sample